dom4j解析xml时，子节点缺少一个元素/标签问题

缺乏、安全感 2024-03-31 08:39 18阅读 0赞

<?xml version = "1.0"?>
    <class>
        <student rollno = "393">
            <firstname>dinkar</firstname>
            <lastname>kad</lastname>
            <nickname>dinkar</nickname>
            <marks>85</marks>
        </student>
    
        <student rollno = "493">
            <lastname>Gupta</lastname>
            <nickname>vinni</nickname>
            <marks>95</marks>
        </student>
    
        <student rollno = "593">
            <firstname>jasvir</firstname>
            <lastname>singn</lastname>
            <nickname>jazz</nickname>
            <marks>90</marks>
        </student>
    </class>

第二个student没有“firstname”标签  
不需要自己写判断  
再套一层即可

File inputFile = new File("input.xml");
    SAXReader reader = new SAXReader();
    Document document = reader.read(inputFile);
    Element classElement = document.getRootElement();
    // 第一种
    classElement.elements().forEach(q->{
        
        if (q.selectSingleNode("firstname") != null) {
        
            System.out.println(q.selectSingleNode("firstname").getText());
        }
    });
    
    // 第二种
    
    document.selectNodes("/class/student").forEach(e->{
        
        e.selectNodes("firstname").forEach(r->{
        
            System.out.println(e.selectSingleNode("firstname").getText());
        });
    });

用list（elements、selectNodes）取节点，文本结果用  
getText取结果  
例如

l.selectNodes("detail").forEach(n->{
        
        n.selectNodes("name").forEach(o->{
        
            System.out.println(o.getText());
        });
        n.selectNodes("value").forEach(p->{
        
            System.out.println(p.getText());
        });
        n.selectNodes("source").forEach(q->{
        
    System.out.println(q.selectSingleNode("type").getText());
    System.out.println(q.selectSingleNode("name").getText());
    System.out.println(q.selectSingleNode("description").getText());
                            });