统计字符数量

左手的ㄟ右手 2024-04-03 12:58 88阅读 0赞

**1** **问题**

在编程中，我们会遇到需要统计一段字符中字符的数量的问题，我们该如何解决这些问题呢？

**2** **方法**

我们可以利用ASKII编码再加上for循环和条件判断来进行转换，这样就可以分别计算出数字、字母、及其他字符的数量

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 <td>package test; import java.util.Scanner; public class Work2 { &nbsp; &nbsp;public static void main(String[] args) { &nbsp; &nbsp; &nbsp; &nbsp;int word = 0; &nbsp; &nbsp; &nbsp; &nbsp;int space= 0; &nbsp; &nbsp; &nbsp; &nbsp;int num = 0; &nbsp; &nbsp; &nbsp; &nbsp;int other = 0; &nbsp; &nbsp; &nbsp; &nbsp;Scanner s = new Scanner(System.in); &nbsp; &nbsp; &nbsp; &nbsp;System.out.println("请输入字符："); &nbsp; &nbsp; &nbsp; &nbsp;String str = s.nextLine(); &nbsp; &nbsp; &nbsp; &nbsp;char[] arr = new char[str.length()]; &nbsp; &nbsp; &nbsp; &nbsp;for (int i = 0; i &lt; str.length(); i++) { &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;char a = str.charAt(i); &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;if ((int) a &gt;= 65 &amp;&amp; (int) a &lt;= 90 || (int) a &gt;= 97 &amp;&amp; (int) a &lt;= 122) { &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;word++; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;} else if ((int) a == 32) { &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;space++; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;} else if ((int) a &gt;= 48 &amp;&amp; (int) a &lt;= 57) { &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;num++; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;} else { &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;other++; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;} &nbsp; &nbsp; &nbsp; &nbsp;} &nbsp; &nbsp; &nbsp; &nbsp;System.out.println("英文字母有：" + word + "个"); &nbsp; &nbsp; &nbsp; &nbsp;System.out.println("空格有：" + space + "个"); &nbsp; &nbsp; &nbsp; &nbsp;System.out.println("数字有：" + num + "个"); &nbsp; &nbsp; &nbsp; &nbsp;System.out.println("其他字符：" + other + "个"); &nbsp; &nbsp;} }</td> 
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**3** **结语**

针对如何计算字符串数量的问题，提出通过利用ASKII编码和循环判断的方法，通过java的编程实验，证明该方法是有效的，本文只是单纯对字母，数字及空格进行区分，之后还可以更加细节。例如大小写也进行区分。