XML格式文档解析

旧城等待， 2024-04-17 16:50 11阅读 0赞

*  [XML格式文档解析][XML]
    
     *  [背景][Link 1]
     *  [code][]
        
         *   *  [bean类][bean]
     *  [遇到的问题][Link 2]
        
         *  [xml文件找不到][xml]

# XML格式文档解析 #

## 背景 ##

> 大数据平台项目中要对中国省级行政区名称定制一个清洗规则，规则中希望，如果有不正规的省份名称，需要进行改进，对数据进行修正，比如 香港 -> 香港特别行政区, 宁夏-> 宁夏回族自治区， 所以将所有标准省份名称放入xml文件中，并对xml文件进行解析，读取到内存中，所以特此记录一下

## code ##

import java.io.InputStream;
    import java.util.ArrayList;
    import java.util.List;
    
    import javax.xml.parsers.DocumentBuilder;
    import javax.xml.parsers.DocumentBuilderFactory;
    import javax.xml.parsers.ParserConfigurationException;
    
    
    import org.w3c.dom.Document;
    import org.w3c.dom.NamedNodeMap;
    import org.w3c.dom.Node;
    import org.w3c.dom.NodeList;
    import parquet.org.slf4j.Logger;
    import parquet.org.slf4j.LoggerFactory;
    
    /**
     * 用DOM方式读取xml文件
     * @author wangyg
     */
    public class ReadxmlByDom {
        private static  final Logger LOG = LoggerFactory.getLogger(ReadxmlByDom.class);
    
        private static DocumentBuilderFactory dbFactory = null;
        private static DocumentBuilder db = null;
        private static Document document = null;
        private static List<Province> provinceList = null;
        static{
            try {
                dbFactory = DocumentBuilderFactory.newInstance();
                db = dbFactory.newDocumentBuilder();
            } catch (ParserConfigurationException e) {
                e.printStackTrace();
            }
        }
    
        public static List<Province> getBooks(String fileName) throws Exception{
            //将给定 URI 的内容解析为一个 XML 文档,并返回Document对象
            InputStream in = ReadxmlByDom.class.getClassLoader().getResourceAsStream(fileName);
            if(in == null){
                LOG.error("in is null ...");
                return null;
            }
            document = db.parse(in);
            //按文档顺序返回包含在文档中且具有给定标记名称的所有 Element 的 NodeList
            NodeList bookList = document.getElementsByTagName("Province");
            provinceList = new ArrayList<>();
            //遍历books
            for(int i=0;i<bookList.getLength();i++){
                Province pro = new Province();
                //获取第i个book结点
                org.w3c.dom.Node node = bookList.item(i);
                //获取第i个book的所有属性
                NamedNodeMap namedNodeMap = node.getAttributes();
                //获取已知名为id的属性值
                String id = namedNodeMap.getNamedItem("ID").getTextContent();
                pro.setID(Integer.parseInt(id));
                //获取book结点的子节点,包含了Test类型的换行
                NodeList cList = node.getChildNodes();
    
                Node item = cList.item(0);
                pro.setProvinceName(item.getNodeValue());
                provinceList.add(pro);
            }
    
            return provinceList;
    
        }
    
        public static void main(String args[]){
            String fileName = "Provinces.xml";
            try {
                List<Province> list = ReadxmlByDom.getBooks(fileName);
                for(Province pro :list){
                    System.out.println(pro);
                }
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
    
    }

bean类

package com.qjzh.etown.bdp.util;
    
    public class Province {
        private  int ID;
        private String ProvinceName;
    
    
        public int getID() {
            return ID;
        }
    
        public void setID(int ID) {
            this.ID = ID;
        }
    
        public String getProvinceName() {
            return ProvinceName;
        }
    
        public void setProvinceName(String provinceName) {
            ProvinceName = provinceName;
        }
    
        @Override
        public String toString() {
            return "Province{" +
                    "ID=" + ID +
                    ", ProvinceName='" + ProvinceName + '\'' +
                    '}';
        }
    }

## 遇到的问题 ##

### xml文件找不到 ###

将xml文件放在resources目录下，未找到，不能访问

解决：查看源码中的接口,可以使用inputStream， 所以就用下面这种方式处理

//filename就是xml文件名称
     InputStream in = ReadxmlByDom.class.getClassLoader().getResourceAsStream(fileName);
            if(in == null){
                LOG.error("in is null ...");
                return null;
            }
            document = db.parse(in);

参考链接

> [https://blog.csdn.net/zflovecf/article/details/78908788][https_blog.csdn.net_zflovecf_article_details_78908788]

[XML]: https://note.youdao.com/md/preview.html?file=%2Fyws%2Fapi%2Fpersonal%2Ffile%2F006C678ECD7E4F20B4B65AF0FE098D8F%3Fmethod%3Ddownload%26read%3Dtrue%26shareKey%3D0e03b2d1b08fff3442ae29102d85be06#xml%E6%A0%BC%E5%BC%8F%E6%96%87%E6%A1%A3%E8%A7%A3%E6%9E%90
[Link 1]: https://note.youdao.com/md/preview.html?file=%2Fyws%2Fapi%2Fpersonal%2Ffile%2F006C678ECD7E4F20B4B65AF0FE098D8F%3Fmethod%3Ddownload%26read%3Dtrue%26shareKey%3D0e03b2d1b08fff3442ae29102d85be06#%E8%83%8C%E6%99%AF
[code]: https://note.youdao.com/md/preview.html?file=%2Fyws%2Fapi%2Fpersonal%2Ffile%2F006C678ECD7E4F20B4B65AF0FE098D8F%3Fmethod%3Ddownload%26read%3Dtrue%26shareKey%3D0e03b2d1b08fff3442ae29102d85be06#code
[bean]: https://note.youdao.com/md/preview.html?file=%2Fyws%2Fapi%2Fpersonal%2Ffile%2F006C678ECD7E4F20B4B65AF0FE098D8F%3Fmethod%3Ddownload%26read%3Dtrue%26shareKey%3D0e03b2d1b08fff3442ae29102d85be06#bean%E7%B1%BB
[Link 2]: https://note.youdao.com/md/preview.html?file=%2Fyws%2Fapi%2Fpersonal%2Ffile%2F006C678ECD7E4F20B4B65AF0FE098D8F%3Fmethod%3Ddownload%26read%3Dtrue%26shareKey%3D0e03b2d1b08fff3442ae29102d85be06#%E9%81%87%E5%88%B0%E7%9A%84%E9%97%AE%E9%A2%98
[xml]: https://note.youdao.com/md/preview.html?file=%2Fyws%2Fapi%2Fpersonal%2Ffile%2F006C678ECD7E4F20B4B65AF0FE098D8F%3Fmethod%3Ddownload%26read%3Dtrue%26shareKey%3D0e03b2d1b08fff3442ae29102d85be06#xml%E6%96%87%E4%BB%B6%E6%89%BE%E4%B8%8D%E5%88%B0
[https_blog.csdn.net_zflovecf_article_details_78908788]: https://blog.csdn.net/zflovecf/article/details/78908788