Java读取指定文件夹下所有文件路径

快来打我* 2022-04-25 06:26 328阅读 0赞

最近有一个合作的大型项目准备上线，需要罗列文件清单。为了提高效率，决定编写一个JAVA程序去读取所有的文件路径。写入指定的文件中，代码及测试截图如下。将代码copy到工程中启动main方法直接测试即可。

package demoFile;
    import java.io.File;
    import java.io.FileInputStream;
    import java.io.FileOutputStream;
    
    public class FilePath {
    	public static void main(String[] args) {
    		String desFiler="D:\\test\\bbb";
    		String scrfiler="D:\\test\\aaaaa.txt";
    		copyFile(scrfiler,desFiler);
    	}
    	private static void copyFile(String scrFile,String desFile) {
    		String newFileName=scrFile.substring(scrFile.lastIndexOf("\\")+1);
    		System.out.println(newFileName);
    		desFile=desFile+File.separator+newFileName;
    		System.out.println(desFile);
    		try {
    			FileInputStream fis=new FileInputStream(scrFile);
    			FileOutputStream fos=new FileOutputStream(desFile);
    			byte[] datas=new byte[1024*8];
    			int len=0;
    			while((len=fis.read(datas))!=-1){
    				 fos.write(datas,0,len);
    			}
    			fis.close();
    			fos.close();
    		} catch (Exception e) {
    			// TODO Auto-generated catch block
    			e.printStackTrace();
    		}
    		
    	}
    }

package demoFile;
    
    import java.io.File;
    import java.io.PrintWriter;
    import java.util.ArrayList;
    import java.util.Arrays;
    
    public class FileGetPath {
    	public static void main(String[] args) {
    		try {
    		ArrayList<String> listFileName=new ArrayList<String>();
    		getFileName("D:\\test\\", listFileName); 	//需要读取的文件位置
    		String desFile="D:\\test1\\bcc.txt";		//输出文件的位置
    		PrintWriter pw=new PrintWriter(desFile);
    		for (String name : listFileName) {
    			if(name.contains(".txt")||name.contains(".class")){	//文件类型
    				System.out.println(name);
    				pw.println(name);
    			}
    		}
    		pw.close();
    		} catch (Exception e) {
    			e.printStackTrace();
    		}
    	}
    	public static void getFileName(String path,ArrayList<String> listFileName){
    		File file =new File(path);
    		File[] files=file.listFiles();
    		String[] names= file.list();
    		if(names!=null){
    			String[] completName= new String[names.length];
    			for(int i=0;i<names.length;i++){
    				completName[i]=path+names[i];
    			}
    			listFileName.addAll(Arrays.asList(completName));
    		}
    		for (File a : files) {
    			if(a.isDirectory()){ 				//判断有子文件
    				getFileName(a.getAbsolutePath()+"\\", listFileName);
    			}
    		}
    	}
    }

package demoFile;
    import java.io.BufferedReader;
    import java.io.File;
    import java.io.FileInputStream;
    import java.io.FileOutputStream;
    import java.io.InputStreamReader;
    
    public class FilePath {
    	public static void main(String[] args) {
    		InputReader("D:\\test1\\bcc.txt","D:\\test1\\ccc");
    	}
    	public static void InputReader(String srcName,String desName) {
    		try {
    			File file = new File(srcName);
    			InputStreamReader inputReader = new InputStreamReader(new FileInputStream(file));
    			BufferedReader bf = new BufferedReader(inputReader);
    			String srcStr;
    			while ((srcStr = bf.readLine()) != null) {
    				if(srcStr.contains("\\")){
    					String filePath=srcStr.substring(2,srcStr.lastIndexOf("\\"));
    					File fs=new File(desName+filePath);
    					fs.mkdirs();
    					copyFile(srcStr,desName+filePath);
    				}
    			}
    			bf.close();
    			inputReader.close();
    		} catch (Exception e) {
    			e.printStackTrace();
    		}
    	}
    	private static void copyFile(String scrFile,String desFile) {
    		String newFileName=scrFile.substring(scrFile.lastIndexOf("\\")+1);
    		System.out.println(newFileName);
    		desFile=desFile+File.separator+newFileName;
    		System.out.println(desFile);
    		try {
    			FileInputStream fis=new FileInputStream(scrFile);
    			FileOutputStream fos=new FileOutputStream(desFile);
    			byte[] datas=new byte[1024*8];
    			int len=0;
    			while((len=fis.read(datas))!=-1){
    				 fos.write(datas,0,len);
    			}
    			fis.close();
    			fos.close();
    		} catch (Exception e) {
    			e.printStackTrace();
    		}
    		
    	}
    }