js获取多个select下拉框选中的值 清疚 2022-02-26 20:20 481阅读 0赞 js获取多个select下拉框选中的值 var electronicIds = \[\]; $("select\[name='electronicId'\]").each(function(j,item)\{ electronicIds.push(document.getElementsByTagName("select")\[j\].value); \}); 例子: var row= "<div class='table-style'>" +"<div class='row' id='addRow'>" +"<div class='col-sm-1 col-xs-4'><span>\*</span>电子券:</div>" +"<div class='col-sm-3 col-xs-8 div-select'>" +"<select class='form-control dselect' name='electronicId' id='select'>" +"<option value='' label='' title=''>---请选择---</option>" +"<\#list elist as list>" +"<option value='$\{(list.id)!\}' label='$\{(list.typeSign)!\}' title='$\{(list.reduceMoney)!\}'>$\{(list.title)!\}</option>" +"</\#list>" +"</select>" +"</div>" +"<div class='col-sm-4 col-xs-12'><button class='btn btn-sm btn-danger ' οnclick='delRow(this)'>删除</button></div>" +"</div>" +"</div>"; $("\#baseinfo2").append(row);
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