计算两个经纬度点间的距离

你的名字 2021-10-25 13:30 846阅读 0赞

计算两个经纬度点间的距离

纬度线投射在图上看似水平的平行线，但实际上是不同半径的圆。有相同特定纬度的所有位置都在同一个纬线上。   
赤道的纬度为0°，将行星平分为南半球和北半球。   
纬度是指某点与地球球心的连线和地球赤道面所成的线面角，其数值在0至90度之间。位于赤道以北的点的纬度叫北纬，记为N，位于赤道以南的点的纬度称南纬，记为S。  
纬度数值在0至30度之间的地区称为低纬地区，纬度数值在30至60度之间的地区称为中纬地区，纬度数值在60至90度之间的地区称为高纬地区。  
赤道、南回归线、北回归线、南极圈和北极圈是特殊的纬线。  
纬度1秒的长度  
地球的子午线总长度大约40008km。平均：  
纬度1度 = 大约111km   
纬度1分 = 大约1.85km   
纬度1秒 = 大约30.9m

The haversine formula

在球上任意两个点的距离有如下关系：

![202111249096157.png][]

![202113078158862.png][]

其中，d:两点间距离，既球面距离；

r：球的半径；

![202148074249838.png][]：点1和点2的纬度；

![202148232535606.png][]：点1和点2的经度；

![202151420495041.png][]

![202151519245491.png][]

Java版：

![ContractedBlock.gif][] ![ExpandedBlockStart.gif][]

1 import com.google.android.maps.GeoPoint;
     2 
     3 public class DistanceCalculator {
     4 
     5    private double Radius;
     6 
     7    // R = earth's radius (mean radius = 6,371km)
     8    // Constructor
     9    DistanceCalculator(double R) {
    10       Radius = R;
    11    }
    12 
    13    public double CalculationByDistance(GeoPoint StartP, GeoPoint EndP) {
    14       double lat1 = StartP.getLatitudeE6()/1E6;
    15       double lat2 = EndP.getLatitudeE6()/1E6;
    16       double lon1 = StartP.getLongitudeE6()/1E6;
    17       double lon2 = EndP.getLongitudeE6()/1E6;
    18       double dLat = Math.toRadians(lat2-lat1);
    19       double dLon = Math.toRadians(lon2-lon1);
    20       double a = Math.sin(dLat/2) * Math.sin(dLat/2) +
    21          Math.cos(Math.toRadians(lat1)) * Math.cos(Math.toRadians(lat2)) *
    22          Math.sin(dLon/2) * Math.sin(dLon/2);
    23       double c = 2 * Math.asin(Math.sqrt(a));
    24       return Radius * c;
    25    }
    26 }

C\#版：

![ContractedBlock.gif][] ![ExpandedBlockStart.gif][]

1 using System;
     2 namespace HaversineFormula
     3 {
     4     /// <summary>
     5     /// The distance type to return the results in.
     6     /// </summary>
     7     public enum DistanceType { Miles, Kilometers };
     8     /// <summary>
     9     /// Specifies a Latitude / Longitude point.
    10     /// </summary>
    11     public struct Position
    12     {
    13         public double Latitude;
    14         public double Longitude;
    15     }
    16     class Haversine
    17     {
    18         /// <summary>
    19         /// Returns the distance in miles or kilometers of any two
    20         /// latitude / longitude points.
    21         /// </summary>
    22         /// <param name=”pos1″></param>
    23         /// <param name=”pos2″></param>
    24         /// <param name=”type”></param>
    25         /// <returns></returns>
    26         public double Distance(Position pos1, Position pos2, DistanceType type)
    27         {
    28             double R = (type == DistanceType.Miles) ? 3960 : 6371;
    29             double dLat = this.toRadian(pos2.Latitude - pos1.Latitude);
    30             double dLon = this.toRadian(pos2.Longitude - pos1.Longitude);
    31             double a = Math.Sin(dLat / 2) * Math.Sin(dLat / 2) +
    32                 Math.Cos(this.toRadian(pos1.Latitude)) * Math.Cos(this.toRadian(pos2.Latitude)) *
    33                 Math.Sin(dLon / 2) * Math.Sin(dLon / 2);
    34             double c = 2 * Math.Asin(Math.Min(1, Math.Sqrt(a)));
    35             double d = R * c;
    36             return d;
    37         }
    38         /// <summary>
    39         /// Convert to Radians.
    40         /// </summary>
    41         /// <param name="val"></param>
    42         /// <returns></returns>
    43         private double toRadian(double val)
    44         {
    45             return (Math.PI / 180) * val;
    46         }
    47     }
    48 }

![ContractedBlock.gif][] ![ExpandedBlockStart.gif][]

1 Position pos1 = new Position();
    2 pos1.Latitude = 40.7486;
    3 pos1.Longitude = -73.9864;
    4 Position pos2 = new Position();
    5 pos2.Latitude = 24.7486;
    6 pos2.Longitude = -72.9864;
    7 Haversine hv = new Haversine();
    8 double result = hv.Distance(pos1, pos2, DistanceType.Kilometers);

JavaScript版：

![ContractedBlock.gif][] ![ExpandedBlockStart.gif][]

1 var R = 6371; // km
    2 var dLat = (lat2-lat1)*Math.PI/180;
    3 var dLon = (lon2-lon1)*Math.PI/180; 
    4 var a = Math.sin(dLat/2) * Math.sin(dLat/2) +
    5         Math.cos(lat1*Math.PI/180) * Math.cos(lat2*Math.PI/180) * 
    6         Math.sin(dLon/2) * Math.sin(dLon/2); 
    7 var c = 2 * Math.asin(Math.sqrt(a)); 
    8 var d = R * c;

Python版：

![ContractedBlock.gif][] ![ExpandedBlockStart.gif][]

1 #coding:UTF-8
     2 """
     3   Python implementation of Haversine formula
     4   Copyright (C) <2009>  Bartek GÃ³rny <bartek@gorny.edu.pl>
     5 
     6   This program is free software: you can redistribute it and/or modify
     7   it under the terms of the GNU General Public License as published by
     8   the Free Software Foundation, either version 3 of the License, or
     9   (at your option) any later version.
    10 
    11   This program is distributed in the hope that it will be useful,
    12   but WITHOUT ANY WARRANTY; without even the implied warranty of
    13   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
    14   GNU General Public License for more details.
    15 
    16   You should have received a copy of the GNU General Public License
    17   along with this program.  If not, see <http://www.gnu.org/licenses/>.
    18 """
    19 
    20 import math
    21 
    22 def recalculate_coordinate(val,  _as=None):
    23   """
    24     Accepts a coordinate as a tuple (degree, minutes, seconds)
    25     You can give only one of them (e.g. only minutes as a floating point number) and it will be duly
    26     recalculated into degrees, minutes and seconds.
    27     Return value can be specified as 'deg', 'min' or 'sec'; default return value is a proper coordinate tuple.
    28   """
    29   deg,  min,  sec = val
    30   # pass outstanding values from right to left
    31   min = (min or 0) + int(sec) / 60
    32   sec = sec % 60
    33   deg = (deg or 0) + int(min) / 60
    34   min = min % 60
    35   # pass decimal part from left to right
    36   dfrac,  dint = math.modf(deg)
    37   min = min + dfrac * 60
    38   deg = dint
    39   mfrac,  mint = math.modf(min)
    40   sec = sec + mfrac * 60
    41   min = mint
    42   if _as:
    43     sec = sec + min * 60 + deg * 3600
    44     if _as == 'sec': return sec
    45     if _as == 'min': return sec / 60
    46     if _as == 'deg': return sec / 3600
    47   return deg,  min,  sec
    48       
    49 
    50 def points2distance(start,  end):
    51   """
    52     Calculate distance (in kilometers) between two points given as (long, latt) pairs
    53     based on Haversine formula (http://en.wikipedia.org/wiki/Haversine_formula).
    54     Implementation inspired by JavaScript implementation from http://www.movable-type.co.uk/scripts/latlong.html
    55     Accepts coordinates as tuples (deg, min, sec), but coordinates can be given in any form - e.g.
    56     can specify only minutes:
    57     (0, 3133.9333, 0) 
    58     is interpreted as 
    59     (52.0, 13.0, 55.998000000008687)
    60     which, not accidentally, is the lattitude of Warsaw, Poland.
    61   """
    62   start_long = math.radians(recalculate_coordinate(start[0],  'deg'))
    63   start_latt = math.radians(recalculate_coordinate(start[1],  'deg'))
    64   end_long = math.radians(recalculate_coordinate(end[0],  'deg'))
    65   end_latt = math.radians(recalculate_coordinate(end[1],  'deg'))
    66   d_latt = end_latt - start_latt
    67   d_long = end_long - start_long
    68   a = math.sin(d_latt/2)**2 + math.cos(start_latt) * math.cos(end_latt) * math.sin(d_long/2)**2
    69   c = 2 * math.asin(math.sqrt(a))
    70   return 6371 * c
    71 
    72 
    73 if __name__ == '__main__':
    74  warsaw = ((21,  0,  30),  (52, 13, 56))
    75  cracow = ((19, 56, 18),  (50, 3, 41))
    76  print points2distance(warsaw,  cracow)

PHP版：

![ContractedBlock.gif][] ![ExpandedBlockStart.gif][]

1 function getDistance($latitude1, $longitude1, $latitude2, $longitude2) {
     2     $earth_radius = 6371;
     3     
     4     $dLat = deg2rad($latitude2 - $latitude1);
     5     $dLon = deg2rad($longitude2 - $longitude1);
     6     
     7     $a = sin($dLat/2) * sin($dLat/2) + cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * sin($dLon/2) * sin($dLon/2);
     8     $c = 2 * asin(sqrt($a));
     9     $d = $earth_radius * $c;
    10     
    11     return $d;
    12 }

参考地址：
    http://www.codecodex.com/wiki/Calculate_distance_between_two_points_on_a_globe
    http://en.wikipedia.org/wiki/Haversine_formula

转载于:https://www.cnblogs.com/thinkquan/p/3925199.html

[202111249096157.png]: /images/20211025/70b271456178444996a7d1abd8c4459d.png
[202113078158862.png]: /images/20211025/44f0bf870f94427eb9453cdeff1d5a7f.png
[202148074249838.png]: /images/20211025/328372bde1cf4fa3bc9466e8e8ef10fa.png
[202148232535606.png]: /images/20211025/a2a9a8f0d8224b33a9c9ef9396e4ee82.png
[202151420495041.png]: /images/20211025/239e990c8749452cb523a6e4a4d8dcb5.png
[202151519245491.png]: /images/20211025/cd24937383074adabfbafb0b90521b23.png
[ContractedBlock.gif]: https://images.cnblogs.com/OutliningIndicators/ContractedBlock.gif
[ExpandedBlockStart.gif]: /images/20211025/76a1c335207a4436882948a541583aff.png

计算两个经纬度点间的距离

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