数组逆序

ゝ一纸荒年。 2024-03-22 17:20 63阅读 0赞

**1** **问题**

原数组存储元素为\{11，22，33，44，55\}，逆序输出数组\{55，44，33，22，11\}。

**2** **方法**

首先我们要调用逆序的方法和遍历的方法，利用循环实现数组遍历，遍历的过程中，最远的两端换位。定义两个变量，对数组中的元素进行位置交换，min索引和max索引的元素交换。再定义变量保存min索引，将max索引的元素赋值给min索引。最后定义一个方法实现数组的遍历。

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 <td>package blog; public class Test02 { &nbsp; &nbsp;public static void main(String[] args) { &nbsp; &nbsp; &nbsp; &nbsp;int[] arr = {11,22,33,44,55}; &nbsp; &nbsp; &nbsp; &nbsp;reverse(arr); &nbsp; &nbsp; &nbsp; &nbsp;printArray(arr); &nbsp; &nbsp;} &nbsp; &nbsp;public static void reverse(int[] array) { &nbsp; &nbsp; &nbsp; &nbsp;for(int min = 0,max = array.length-1;min&lt;max;min++,max--){ &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;int temp = array[min]; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;array[min] = array[max]; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;array[max] = temp; &nbsp; &nbsp; &nbsp; &nbsp;} &nbsp; &nbsp;} &nbsp; &nbsp;public static void printArray(int[] array){ &nbsp; &nbsp; &nbsp; &nbsp;System.out.println("["); &nbsp; &nbsp; &nbsp; &nbsp;for (int i=0;i&lt;array.length;i++){ &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;if(i==array.length-1){ &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;System.out.println(array[i]+"]"); &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;}else{ &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;System.out.println(array[i]+","); &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;} &nbsp; &nbsp; &nbsp; &nbsp;} &nbsp; &nbsp;} }</td> 
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**3** **结语**

要实现数组元素的逆序，就是要把数组中索引为start与end的元素进行互换。每次互换后，start索引位置后移，end索引位置前移，再进行互换。知道start位置超越了end位置，互换结束，数组元素逆序就完成了。