用Python登录账户

ゞ浴缸里的玫瑰 2024-03-04 07:44 86阅读 0赞

**1** **问题**

如何利用python登录账户？

**2** **方法**

1.  账户和密码存放在文件夹中
2.  从文件夹中读取并比较密码密文
3.  验证三次后，如不成功则锁定用户

![c2fd434f5c03b748b731a7cdeff532ac.png][]

通过。。。。。。。。等证明提出的方法是有效的，能够解决开头提出的问题。

代码清单 1

<table> 
 <tbody> 
 <tr> 
 <td>import os import getpass #认证次数，初始值为0 times = 0 while times &lt; 3: &nbsp; &nbsp; &nbsp;UserName ='aa' #初始化，后面校验是否存在输入的用户 &nbsp; &nbsp; &nbsp;UserName = input(" 请输入用户名: ") &nbsp; &nbsp; &nbsp;PassWord = getpass. getpass(" 请输入密码: ") &nbsp; &nbsp; &nbsp; #将账户与列表引入，以只读的方式。 &nbsp; &nbsp; &nbsp; with open(" configf'userlist.txt", r') as f： &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; for userlist in f: &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;#判断账户是否存在与文本中 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;if userlist. find (UserName) != -1 ： &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;#print (type (userlist. find (UserName))) &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; _UserName,_ PassWord = userlist. strip0). split(,' ) &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; break &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; else： &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; #_ _UserName = ' aa continue &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;if_ UserName ==' aa' ： &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; print("用户”+ UserName +”不存在”) &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;continue &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;if UserName ==__ UserName and PassWord !=_ PassWord： &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; print ("密码不对”) &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; elif： &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; UserName==__UserName and FassWord==_ FassWord &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; print("欢迎回来”) &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; break &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; else： &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;print("再检查一次吧”) &nbsp; &nbsp; &nbsp; &nbsp;times += 1 else： &nbsp; print("用户已锁定，请稍后重试! ") &nbsp; &nbsp; with open(" configl lockuser. txt" ,a+') as 1: 
 <ol> 
 <li>write (UserName + ' \n' )</li> 
 </ol></td> 
 </tr> 
 </tbody> 
</table>

**3** **结语**

针对用Python登录账户的问题，提出以上方法，通过本次实验，证明该方法是有效的，本次实验的方法有些繁琐，可以通过未来的学习对该方法进行简化和优化。

[c2fd434f5c03b748b731a7cdeff532ac.png]: https://image.dandelioncloud.cn/pgy_files/images/2024/03/04/26dfbb1d73f6451f8e12684cdb887815.png