C语言 16进制数组转 ASCII字符串函数

末蓝、 2022-12-23 14:27 204阅读 0赞

C语言 16进制数组 转 ASCII字符串函数  
RET\_SUCCESS、RET\_FAILURE需自行定义  
转换后的数组，其最后一个元素必须是’\\0’，代表字符串结束

/** **************************************************************************************** * @brief convert uint8_t array_a[n] to char array_b[2*n + 1] * @param[in] pHex: input array[], hex format * @param[out] pAscii: output array[], ascii format * @param[in] hex_len: input array[]'s size * @note if input_array[]'s size is n, the out_array[]'s size is 2n+1 * @retval RET_SUCCESS: operation success RET_FAILURE: operation failed **************************************************************************************** */
    static int HexToAscii(uint8_t* pHex, char *pAscii, uint8_t hex_len)
    { 
        uint8_t hex_data[2] = { 0x00};  
        for (uint16_t i = 0; i < hex_len; i++)
        { 
            hex_data[0] = (pHex[i] & 0xF0) >> 4;
            hex_data[1] = pHex[i] & 0x0F;
            for (uint16_t j = 0; j < 2; j++)
            { 
                //0-9 convert
                if(hex_data[j] < 10)
                {             
                    hex_data[j] += 0x30; //0x30 is '0'
                }
                //A-F convert 
                else if(hex_data[j] < 16)
                { 
                    hex_data[j] = hex_data[j] - 10 + 0x41; //0x41 is 'A' 
                }
                else
                { 
                    return RET_FAILURE;
                }
                *pAscii++ = hex_data[j];
            }               
        }
        return RET_SUCCESS;  
    }