leetcode 68. 文本左右对齐模拟

左手的ㄟ右手 2022-12-16 06:00 166阅读 0赞

**不断尝试，考虑各种情况**

#define debug(x) cout<<#x<<": "<<(x)<<endl;
    
    class Solution { 
    public:
        vector<string> fullJustify(vector<string>& words, int maxWidth) { 
            vector<string> ret;
            vector<string>space;
            for(int i=0;i<maxWidth;i++){ 
                space.push_back( string(i,' ') );
                //debug(string(i,'2'))
            }
            string temp = "";
            int tlen = 0;
            int tcnt = 0;
            int pos = 0;
            int i=0;
            
            for(i = 0;pos + i< words.size();){ 
                //debug(words[pos+i])
                    
                if(tlen + words[pos+i].size() < maxWidth){ 
                    tlen += words[pos+i].size() + 1;
                    tcnt++;
                    i++;
                    continue; 
                    
                }
                
                if(tlen + words[pos + i].size() == maxWidth ){ 
                    
                    tlen += words[pos+i].size();
                    tcnt++;
                    
                    int resSp = maxWidth - tlen;
                    if(tcnt==1){ 
                        temp += words[pos];
                    }else{ 
                        int eachlen = resSp / (tcnt-1); 
                        int res = resSp % (tcnt-1);
                        
                        for(int j=0;j < tcnt-1;j++){ 
                            temp += words[pos+j] + space[1] +(eachlen>0?space[eachlen]:"") +
                                (j < res?space[1] :"");
                        }
                        temp += words[pos+tcnt-1];
                    }
                    pos += i+1;
                    
                }
                else{ 
                    
                    tlen--;
                    int resSp = maxWidth - tlen;
                    
                    if(tcnt==1){ 
                        temp += words[pos] + space[resSp];
                    }else{ 
                        //["Listen ","to ","many, ","speak ","to a","few. "]
                        //["Listen","to ","many, ","speak ","to a","few. "]
                        int eachlen = resSp / (tcnt-1); 
                        int res = resSp % (tcnt-1);
                        
                        for(int j=0;j < tcnt-1;j++){ 
                            temp += words[pos+j] + space[1] +(eachlen>0?space[eachlen]:"") +
                                (j < res?space[1] :"");
                        }
                        temp += words[pos+tcnt-1];
                    }
                    pos += i;
                }
                
                
                ret.push_back(temp);
                temp = "";
                tlen = 0;
                tcnt = 0;
                i=0;
                
            }
            
            //debug(tcnt)
                //debug(tlen)
            int resSp = maxWidth - tlen;
            if(tcnt==0){ 
                return ret;
            }
            if(tcnt==1){ 
                temp += words[pos] + " ";
                temp += space[resSp];
            }else{ 
                int eachlen = resSp / (tcnt-1); 
                int res = resSp % (tcnt-1);
                
                //debug(eachlen)
                for(int j=0;j < tcnt;j++){ 
                    temp += words[pos+j] + space[1] ;
                }
                temp += space[maxWidth-temp.size()];
            }
            ret.push_back(temp);
            //["This idds addn","exae of text","justification. "]
            return ret;
        }
    };

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