情人节手写玫瑰花

落日映苍穹つ 2022-11-30 15:48 139阅读 0赞

<!DOCTYPE html>
    <html lang="en">
    	<head>
    		<meta charset="UTF-8">
    		<title>Title</title>
    	</head>
    	<body>
    		<canvas id="c"></canvas>
    	</body>
    </html>
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    	var a = c.getContext('2d');
    	document.body.clientWidth;
    
    	with(m = Math) C = cos, S = sin, P = pow, R = random;
    	c.width = c.height = f = 600;
    	h = -250;
    
    	function p(a, b, c) { 
    		if (c > 60) return [S(a * 7) * (13 + 5 / (.2 + P(b * 4, 4))) - S(b) * 50, b * f + 50, 625 + C(a * 7) * (13 + 5 / (.2 +
    			P(b * 4, 4))) + b * 400, a * 1 - b / 2, a];
    		A = a * 2 - 1;
    		B = b * 2 - 1;
    		if (A * A + B * B < 1) { 
    			if (c > 37) { 
    				n = (j = c & 1) ? 6 : 4;
    				o = .5 / (a + .01) + C(b * 125) * 3 - a * 300;
    				w = b * h;
    				return [o * C(n) + w * S(n) + j * 610 - 390, o * S(n) - w * C(n) + 550 - j * 350, 1180 + C(B + A) * 99 - j * 300,
    					.4 - a * .1 + P(1 - B * B, -h * 6) * .15 - a * b * .4 + C(a + b) / 5 + P(C((o * (a + 1) + (B > 0 ? w : -w)) / 25),
    						30) * .1 * (1 - B * B), o / 1e3 + .7 - o * w * 3e-6
    				]
    			}
    			if (c > 32) { 
    				c = c * 1.16 - .15;
    				o = a * 45 - 20;
    				w = b * b * h;
    				z = o * S(c) + w * C(c) + 620;
    				return [o * C(c) - w * S(c), 28 + C(B * .5) * 99 - b * b * b * 60 - z / 2 - h, z, (b * b * .3 + P((1 - (A * A)), 7) *
    					.15 + .3) * b, b * .7]
    			}
    			o = A * (2 - b) * (80 - c * 2);
    			w = 99 - C(A) * 120 - C(b) * (-h - c * 4.9) + C(P(1 - b, 7)) * 50 + c * 2;
    			z = o * S(c) + w * C(c) + 700;
    			return [o * C(c) - w * S(c), B * 99 - C(P(b, 7)) * 50 - c / 3 - z / 1.35 + 450, z, (1 - b / 1.2) * .9 + a * .1, P((1 -
    				b), 20) / 4 + .05]
    		}
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    	setInterval(
    		'for(i=0;i<1e4;i++)if(s=p(R(),R(),i%46/.74)){z=s[2];x=~~(s[0]*f/z-h);y=~~(s[1]*f/z-h);if(!m[q=y*f+x]|m[q]>z)m[q]=z,a.fillStyle="rgb("+~(s[3]*h)+","+~(s[4]*h)+","+~(s[3]*s[3]*-80)+")",a.fillRect(x,y,1,1)}',
    		0)
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