python日志配置文件解释,从Python日志记录的YAML配置文件中评估语句

桃扇骨 2022-08-30 06:18 154阅读 0赞

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Consider the following snippet of a Python logging YAML config file:

version: 1

formatters:

simple:

format: '%(asctime)s - %(name)s - %(levelname)s - %(message)s'

handlers:

logfile:

class: logging.handlers.TimedRotatingFileHandler

level: DEBUG

filename: some\_fancy\_import\_name.generate\_filename\_called\_error

backupCount: 5

formatter: simple

I would like to load this YAML config file this way:

with open('logging.yaml', 'r') as fd:

config = yaml.safe\_load(fd.read())

logging.config.dictConfig(config)

Take special notice of the filename to which the handler should write logs. In normal Python code, I would expect some\_fancy\_import\_name.generate\_filename\_called\_errorlog to generate the string 'error.log'. All in all, I would like to say that this logging handler should write to the file 'error.log' in the current directory.

However, as it turns out, this is not the case. When I look at the current directory, I see a file named 'some\_fancy\_import\_name.generate\_filename\_called\_errorlog'.

Why go through all this trouble?

I would like filename to be programmatically determined. I have successfully tried configuring logging using normal Python scripting this way:

\# fancy import name

from os import environ as env

\# Programmatically determine filename path

log\_location = env.get('OPENSHIFT\_LOG\_DIR', '.')

log\_filename = os.path.join(log\_location, 'error')

handler = logging.handlers.TimedRotatingFileHandler(log\_filename)

See how the log\_filename path was inferred from environment variables.

I would like to translate this to a YAML config file. Is it possible?

Perhaps I might need to dig through the dict produced by yaml.safe\_load(fd.read()) and do some eval() stuff?

解决方案