C语言实现简单的万年历

冷不防 2022-07-13 03:38 136阅读 0赞

//C语言实现简单的日历 ,输入年份,就会输出整年的日历

#include <stdio.h>
    #include <conio.h>
    
    #include <windows.h>
    
    
    
    long int f(int year, int month)
    {/*f(年，月)＝年－1，如月<3;否则，f(年，月)＝年*/
    	if (month<3) return year - 1;
    	else return year;
    }
    
    long int g(int month)
    {/*g(月)＝月＋13，如月<3;否则，g(月)＝月＋1*/
    	if (month<3) return month + 13;
    	else return month + 1;
    }
    
    long int n(int year, int month, int day)
    {
    	/*N=1461*f(年、月)/4+153*g(月)/5+日*/
    	return 1461L * f(year, month) / 4 + 153L * g(month) / 5 + day;
    }
    
    int w(int year, int month, int day)
    {
    	/*w=(N-621049)%7(0<=w<7)*/
    	return(int)((n(year, month, day) % 7 - 621049L % 7 + 7) % 7);
    }
    
    int date[12][6][7];
    int day_tbl[][12] = { { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 },
    { 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 } };
    main()
    {
    	int sw, leap, i, j, k, wd, day;
    	int year;/*年*/
    	char title[] = "SUN MON TUE WED THU FRI SAT";
    
    	OpenURL();
    
    	printf("Please input the year whose calendar you want to know: ");/*输入年*/
    	scanf("%d%*c", &year);/*输入年份值和掠过值后的回车*/
    	sw = w(year, 1, 1);
    	leap = year % 4 == 0 && year % 100 || year % 400 == 0;/*判闰年*/
    	for (i = 0; i<12; i++)
    	for (j = 0; j<6; j++)
    	for (k = 0; k<7; k++)
    		date[i][j][k] = 0;/*日期表置0*/
    	for (i = 0; i<12; i++)/*一年十二个月*/
    	for (wd = 0, day = 1; day <= day_tbl[leap][i]; day++)
    	{/*将第i＋1月的日期填入日期表*/
    		date[i][wd][sw] = day;
    		sw = ++sw % 7;/*每星期七天，以0至6计数*/
    		if (sw == 0) wd++;/*日期表每七天一行，星期天开始新的一行*/
    	}
    
    	printf("\n|==================The Calendar of Year %d =====================|\n|", year);
    	for (i = 0; i<6; i++)
    	{/*先测算第i+1月和第i+7月的最大星期数*/
    		for (wd = 0, k = 0; k<7; k++)/*日期表的第六行有日期，则wd!=0*/
    			wd += date[i][5][k] + date[i + 6][5][k];
    		wd = wd ? 6 : 5;
    		printf("%2d  %s  %2d  %s |\n|", i + 1, title, i + 7, title);
    		for (j = 0; j<wd; j++)
    		{
    			printf("   ");/*输出四个空白符*/
    			/*左栏为第i+1月，右栏为第i+7月*/
    			for (k = 0; k<7; k++)
    			if (date[i][j][k])
    				printf("%4d", date[i][j][k]);
    			else printf("    ");
    			printf("     ");/*输出十个空白符*/
    			for (k = 0; k<7; k++)
    			if (date[i + 6][j][k])
    				printf("%4d", date[i + 6][j][k]);
    			else printf("    ");
    			printf(" |\n|");
    		}
    		/*scanf("%*c");/*键入回车输出下一个月的日历*/
    
    	}
    	puts("=================================================================|");
    	puts("\n Press any key to quit...");
    	getch();
    }

运行结果如图: