JAVA 时分秒累加

灰太狼 2022-06-02 05:50 231阅读 0赞

一、简介

有个需求是，累加通话时长，把上次通话时长加上本次通话时长，依次累加。

二、实现

@Test
        public void TestA() throws ParseException {
    
                SimpleDateFormat myFormatter = new SimpleDateFormat("HH:mm:ss");
                SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
    
                //上一次通话时长
                HealthConsultation healthConsultation = new HealthConsultation();
                healthConsultation.setConsultinghours("00:00:08");
    
    
                //呼叫时长 3
                HealthCallStateRecord healthCallStateRecorda = new HealthCallStateRecord();
                healthCallStateRecorda.setCreatedate(format.parse("2017-12-19 17:43:42"));
    
                //本次通话时长 4
                HealthCallStateRecord healthCallStateRecordb = new HealthCallStateRecord();
                healthCallStateRecordb.setCreatedate(format.parse("2017-12-19 18:51:50"));
    
                //4-3的时间 获得两个时间的毫秒时间差异
                long diff = healthCallStateRecordb.getCreatedate().getTime() - healthCallStateRecorda.getCreatedate().getTime();//这样得到的差值是微秒级别
                long nd = 1000 * 24 * 60 * 60;
                long nh = 1000 * 60 * 60;
                long nm = 1000 * 60;
                long ns = 1000;
                // 计算差多少天
                long day = diff / nd;
                // 计算差多少小时
                long hour = diff % nd / nh;
                // 计算差多少分钟
                long min = diff % nd % nh / nm;
                // 计算差多少秒//输出结果
                long sec = diff % nd % nh % nm / ns;
    
                //判断上次是否有通话，如果有通话时长，就都累加
                if(healthConsultation.getConsultinghours() != null){
                    Calendar cal = Calendar.getInstance();
                    cal.setTime(myFormatter.parse(healthConsultation.getConsultinghours()));
                    int shi = (int)cal.get(Calendar.HOUR_OF_DAY)+(int)hour;
                    int fendo = (int)cal.get(Calendar.MINUTE)+(int)min;
                    int miao = (int)cal.get(Calendar.SECOND)+(int)sec;
    
                    //秒大于60设为00,然后判断分是否大于60分钟,如果是则分钟清0,小时加1,否则，分钟加1。
                    if(miao>60){
                        miao=00;
                        if(fendo>60){
                            fendo = 00;
                            shi = shi+1;
                        }else {
                            fendo = fendo + 1;
                        }
                    }
                    Date dates = myFormatter.parse(shi + ":" + fendo + ":" + miao);
                    System.out.println("不为空当前时间 : " + myFormatter.format(dates));
                }else {
                    //如果上次无通话，就把本次时长，设为通话时长。
                    Date dates = myFormatter.parse(hour + ":" + min + ":" + sec);
                    System.out.println("为空当前时间 : " + myFormatter.format(dates));
                }
    
    
        }

输出结果为:

不为空当前时间 : 01:08:16

通话时长为1个多小时。