1104. Sum of Number Segments (20)

女爷i 2022-05-28 07:26 117阅读 0赞

Given a sequence of positive numbers, a *segment* is defined to be a consecutive subsequence. For example, given the sequence \{0.1, 0.2, 0.3, 0.4\}, we have 10 segments: (0.1) (0.1, 0.2) (0.1, 0.2, 0.3) (0.1, 0.2, 0.3, 0.4) (0.2) (0.2, 0.3) (0.2, 0.3, 0.4) (0.3) (0.3, 0.4) (0.4).

Now given a sequence, you are supposed to find the sum of all the numbers in all the segments. For the previous example, the sum of all the 10 segments is 0.1 + 0.3 + 0.6 + 1.0 + 0.2 + 0.5 + 0.9 + 0.3 + 0.7 + 0.4 = 5.0.

**Input Specification:**

Each input file contains one test case. For each case, the first line gives a positive integer N, the size of the sequence which is no more than 105. The next line contains N positive numbers in the sequence, each no more than 1.0, separated by a space.

**Output Specification:**

For each test case, print in one line the sum of all the numbers in all the segments, accurate up to 2 decimal places.

**Sample Input:**

4
    0.1 0.2 0.3 0.4

**Sample Output:**

5.00

--------------------

题目大意：

代码：

#include<stdio.h>
    int main()
    {
        int i,j,n,m,k,t;
        double sum=0,value;
        scanf("%d",&n);
        for(i=0;i<n;i++)
        {
            scanf("%lf",&value);
           sum=sum+(value*(i+1)*(n-i));//改为sum=sum+((i+1)*(n-i)*value);最后两个case通不过不知为什么求指教
        }
        printf("%.2lf",sum);
        return 0;
    }

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