Python 实现英语单词统计和替换

r囧r小猫 2022-04-10 05:10 163阅读 0赞

def count_en(a, word):
            index = 0
            times = 0
            len_str = len(a)
            len_word = len(word)
            while True:
                    index = a.find(word, index)
                    if index == -1:
                            break
                    #第一个词
                    if index != 0:
                            front = a[index-1]
                    else:
                            front = ""
                    #if f is not word it will be my word
                    back_index = (index + len_word)
                    #最后一个词
                    if back_index < len_str:
                            back = a[back_index]
                    else:
                            back = ""
                    index += len_word
                    if front.isalpha() or back.isalpha():
                            continue
                    times+=1
            #print times
            return times

def replace_en(a, word, newword):
            index = 0
            len_word = len(word)
            len_new_word= len(newword)
            new_str = a
            i = 0
            while True:
                    #i+=1
                    #print i
                    index = new_str.find(word, index)
                    if index == -1:
                            break
                    #第一个词
                    front_index = index
                    if index != 0:
                            front = new_str[index-1]
                    else:
                            front = ""
                    #if f is not word it will be my word
                    back_index = (index + len_word)
                    #最后一个词
                    len_t = len(new_str)
                    if back_index < len_t:
                            back = new_str[back_index]
                    else:
                            back = ""
                    #new_word = a[:index-1] 
                    if front.isalpha() or back.isalpha():
                            index += len_word
                            continue
                    else:
                            index += 13
                    ff = new_str[:front_index]
                    bb = new_str[back_index:]
                    new_str = ff + newword + bb
            return new_str