SpringMVC接收页面表单参数

电玩女神 2021-11-10 15:00 410阅读 0赞

转：[http://www.cnblogs.com/luxh/archive/2013/03/14/2960152.html][http_www.cnblogs.com_luxh_archive_2013_03_14_2960152.html]

一个普通的表单。

![14180842-a58a6f40f6164ee398e84db7221c2d58.png][]

表单的代码如下：

<%@ page language="java" contentType="text/html; charset=UTF-8"
        pageEncoding="UTF-8"%>
    <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>Add User</title>
    
    
    <script type="text/javascript">
        //添加用户
        function addUser() {
            var form = document.forms[0];
            form.action = "${pageContext.request.contextPath}/user/addUser1";
            //form.action = "${pageContext.request.contextPath}/user/addUser2";
            //form.action = "${pageContext.request.contextPath}/user/addUser3";
            form.method = "post";
            form.submit();
        }
    </script>
    
    </head>
    <body>
        <form>
            <table>
                <tr>
                    <td>账号</td>
                    <td>
                        <input type="text" name="userName">
                    </td>
                </tr>
                <tr>
                    <td>密码</td>
                    <td>
                        <input type="password" name="password">
                    </td>
                </tr>
                <tr>
                    <td> </td>
                    <td>
                        <input type="button" value="提交" οnclick="addUser()">
                    </td>
                </tr>
            </table>
        </form>
    </body>
    </html>

1、直接把表单的参数写在Controller相应的方法的形参中

@RequestMapping("/addUser1")
        public String addUser1(String userName,String password) {
            System.out.println("userName is:"+userName);
            System.out.println("password is:"+password);
            return "/user/success";
        }

2、通过HttpServletRequest接收

@RequestMapping("/addUser2")
        public String addUser2(HttpServletRequest request) {
            String userName = request.getParameter("userName");
            String password = request.getParameter("password");
            System.out.println("userName is:"+userName);
            System.out.println("password is:"+password);
            return "/user/success";
        }

3、通过一个bean来接收

1）建立一个和表单中参数对应的bean

public class User {
        
        private String userName;
        
        private String password;
    
        public String getUserName() {
            return userName;
        }
    
        public void setUserName(String userName) {
            this.userName = userName;
        }
    
        public String getPassword() {
            return password;
        }
    
        public void setPassword(String password) {
            this.password = password;
        }
    }

2）用这个bean来封装接收的参数

@RequestMapping("/addUser3")
        public String addUser3(User user) {
            System.out.println("userName is:"+user.getUserName());
            System.out.println("password is:"+user.getPassword());
            return "/user/success";
        }

4、通过json数据接收

<%@ page language="java" contentType="text/html; charset=UTF-8"
        pageEncoding="UTF-8"%>
    <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>Add User</title>
    
    <script type="text/javascript" src="${pageContext.request.contextPath}/resource/script/jquery-1.9.1.min.js"></script>
    <script type="text/javascript">
        $(document).ready(function(){
            $("#button_submit").click(function(){
                var name = $("#userName").val();
                var pass = $("#password").val();
                
    
                var user = {userName:name,password:pass};//拼装成json格式
                
                $.ajax({
                    type:"POST",
                    url:"${pageContext.request.contextPath}/user/addUser4",
                    data:user,
                    success:function(data){
                        alert("成功");
                    },
                    error:function(e) {
                        alert("出错："+e);
                    }
                });
            });
        });
    </script>
    
    </head>
    <body>
        <form>
            <table>
                <tr>
                    <td>账号</td>
                    <td>
                        <input type="text" id="userName" name="userName">
                    </td>
                </tr>
                <tr>
                    <td>密码</td>
                    <td>
                        <input type="password" id="password" name="password">
                    </td>
                </tr>
                <tr>
                    <td> </td>
                    <td>
                        <input type="button" id="button_submit" value="提交">
                    </td>
                </tr>
            </table>
        </form>
    </body>
    </html>

依然可以使用bean来接收json数据

@RequestMapping("/addUser4")
        public String addUser4(User user) {
            System.out.println("userName is:"+user.getUserName());
            System.out.println("password is:"+user.getPassword());
            return "/user/success";
        }

5、使用jQuery的serializeArray() 方法序列化表单元素

如果表单元素很多，手工拼装成json数据非常麻烦，可以使用jQuery提供的serializeArray()方法序列化表单元素，返回json数据结构数据。

<%@ page language="java" contentType="text/html; charset=UTF-8"
        pageEncoding="UTF-8"%>
    <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>Add User</title>
    
    <script type="text/javascript" src="${pageContext.request.contextPath}/resource/script/jquery-1.9.1.min.js"></script>
    <script type="text/javascript">
        $(document).ready(function(){
            $("#button_submit").click(function(){
                
                //序列化表单元素，返回json数据
                var params = $("#userForm").serializeArray();
                
                //也可以把表单之外的元素按照name value的格式存进来
                //params.push({name:"hello",value:"man"});
                
                $.ajax({
                    type:"POST",
                    url:"${pageContext.request.contextPath}/user/addUser5",
                    data:params,
                    success:function(data){
                        alert("成功");
                    },
                    error:function(e) {
                        alert("出错："+e);
                    }
                });
            });
        });
    </script>
    
    </head>
    <body>
        <form id="userForm">
            <table>
                <tr>
                    <td>账号</td>
                    <td>
                        <input type="text" id="userName" name="userName">
                    </td>
                </tr>
                <tr>
                    <td>密码</td>
                    <td>
                        <input type="password" id="password" name="password">
                    </td>
                </tr>
                <tr>
                    <td> </td>
                    <td>
                        <input type="button" id="button_submit" value="提交">
                    </td>
                </tr>
            </table>
        </form>
    </body>
    </html>

依然可以使用bean来接收json数据：

@RequestMapping("/addUser5")
        public String addUser5(User user) {
            System.out.println("userName is:"+user.getUserName());
            System.out.println("password is:"+user.getPassword());
            return "/user/success";
        }

[http_www.cnblogs.com_luxh_archive_2013_03_14_2960152.html]: http://www.cnblogs.com/luxh/archive/2013/03/14/2960152.html
[14180842-a58a6f40f6164ee398e84db7221c2d58.png]: /images/20211109/a78df73941c0470da36114e01f203ea7.png