C：统计数组中不重复数组个数

野性酷女 2021-10-29 14:12 417阅读 0赞

C：

#include <stdio.h>
    
    #define SIZE 10
    
    int main() {
       int arr[SIZE] = {1,2,45,2,1,8,-3,0,2,4};
       int tmp[SIZE];
       int count = 0;
       int diff;
       int i, j;
    
       for (i=0; i<SIZE; i++) {
          diff = 1;
          for (j=0; j<count; j++) {
             if (arr[i] == tmp[j]) {
                diff = 0;
                break;  
             }       
          }
          if (diff)
             tmp[count++] = arr[i]; 
       }
    
       for (i=0; i<count; i++) 
          printf("%d ", tmp[i]);
       printf("\ncount: %d\n", count); 
    }

在项目开发过程中遇到需要统计ArrayList中 对象的userId不相同的 对象个数，ArrayList中的数据在查询时，已按照userId 升序排列，所以仿照上述C的写法如下：

int count = 0;
            boolean flag = true;
            List<UserLotteryVO> listVO = new ArrayList<UserLotteryVO>();
            List<UserLotteryVO> tempListVO= new ArrayList<UserLotteryVO>();
            List<UserLottery> listEntity = userLotteryDao.SearchUserLotteryByDrawNum(drawNum);
            for(UserLottery ul : listEntity ) {
                listVO.add(this.convertToUserLotteryHistoryVO(ul));
            }
            for(UserLotteryVO vo : listVO) {
                flag = true;
                for(int i = 0; i < count; i++) {
                    if(i >= count) {
                        break;
                    }
                    if(tempListVO.size() > 0 && (vo.getUserId() == tempListVO.get(i).getUserId())) {
                        flag = false;
                        break;
                    }
                }
                if(flag) {
                    tempListVO.add(vo);
                    count++;
                }
            }
            return count;